To answer this, let's first describe the two areas and obtain the pertinent dimensions from them.
The area of the square hole is 5 cm^2. Since A = s^2, where s is the length of a side of the square, s = +√5 in this situation. +√5 is approx. 2.24 cm.
The area of the round peg is 5 cm^2 also, but the area is calculated using a different formula: A = πr^2, where r is the radius of the circle. Solving for r^2, we get:
r^2 = A/π. Here, r^2 = (5 cm^2)/π = 5π, so that:
r = +√(5π). This is approx. 3.96 cm, and so the diameter is twice that, or 7.93 cm.
So there's plenty of room for the round peg to enter the square hole, but not the other way around!
Answer:
The value is -30
Step-by-step explanation:
Plug -6 in for x in the equation:
3sqrt-6(-6)+4(-6)
-6-4*6
-6-24
-30
Answer:
A. y = cos x
Step-by-step explanation:
The function that we see graphed has the point (0,1), this means whichever trig function f(x) it represents f(0) = 1.
Now, only the cosine function has the property that cos(0) = 1, thus choice A is the correct answer.
Step-by-step explanation:
Answer:
Problem 15)
$40.91
Problem 16)
12.446 cm^2
Step-by-step explanation:
Problem 15)
Gala.
12.8 * 1.35 = 17.28
Honeycrisp.
9 * 1.68 = 15.12
Fuji
7.4 * 1.15 = 8.51
17.28 + 15.12 + 8.51 = 40.91
Problem 16)
(area1) + (area2) + (area3) = (total area)
(1.25*4.38) + (1.36*2.15) + (1.14*3.55) = x
5.475 + 2.924 + 4.047 = x
12.446 = x
Answer:
i would say a senior citizen ticket i 3 dollars and the child tickets are 5 dollars
Step-by-step explanation:
