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3 years ago

GH has a midpoint at M (5,9). Point H is at (8,9). Find the coordinates of point G

Mathematics

1 answer:

natta225 [31]3 years ago

7 0

Answer:

(2,9)

Step-by-step explanation:

The midpoint of a point is halfway between two points. The distance between the midpoint and point H is 3 because the distance from 5 to 8 is 3. Therefore 3 away from 5 would be 2.

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What improper fraction equal to the mix number 4 7/9?

Marianna [84]

Answer:

43/9

Step-by-step explanation:

Step 1

Multiply the denominator by the whole number

9 × 4 = 36

Step 2

Add the answer from Step 1 to the numerator

36 + 7 = 43

Step 3

Write answer from Step 2 over the denominator

43/9

=439

3 0

4 years ago

Movie tickets for 2 adults and 3 children cost $44.50. Tickets for the same movie cost $23.50 for 1 adult and 2 children. How mu

schepotkina [342]

I think it is 45.75. I am sorry if it is wrong.

4 0

3 years ago

Read 2 more answers

At the school store, 3 pens and 2 notebooks cost a total of $12, while 1 pen and 3 notebooks cost a total of $11. This can be re

jasenka [17]

Answer:

Step-by-step explanation:

the reason why is because if you put 3 dollars in for the notebooks right you have 3x3=9 and that one pen will be 2 dollars. Now you have 3×2=6 and then the two notebooks will be 6 and you add that and get 12. Hope this helps

3 0

3 years ago

Read 2 more answers

I need help with these two

jeka57 [31]

Answer:

4)X=23

5)x=15

Step-by-step explanation:

8x-77=3x+38

+77 -3x

5x=115

X=23

———

5x+3+9x-33=180

14x-30=180

+30

14x=180

X=15

7 0

4 years ago

Can someone please help with these 2 word problems ASAP.

PolarNik [594]

Answer:

4. 4.66hours

5. time_trip = 2.777 h

Step-by-step explanation:

4. A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver and Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes 140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route?

We know that

Speed_commercial = distance/ time_comm

Speed_commercial = 1730 km/ time_comm

Then,

Speed_jet = distance/ time_jet = 2*Speed_commercial

Speed_jet = 1730 km/ time_jet = 2*Speed_commercial

time_comm = 2.333 h + time_jet

1730 km/ time_jet = 2*1730 km/ time_comm

time_comm = 2*time_jet

time_comm = 2*(time_comm - 2.333h)

time_comm = (2*time_comm - 4.666h)

time_comm = 4.666 h

5. A man goes fishing in a river and wants to know how long it will take him to get 10km upstream to his favourite fishing location. The speed of the current is 3 km/hr and it takes his boat twice as long to go 3km upstream as is does to go 4km downstream. How long will it take his boat to get to his fishing spot?

Distance = 10 km upstream

Speed_current = 3 km/h

Upstream

(Speed_boat - Speed_current) = 3 km / (2*time_downstream)

Downstream

(Speed_boat + Speed_current) = 4 km / (time_downstream)

We subtract both equations

(Speed_boat + Speed_current) - (Speed_boat - Speed_current) = 4 km / (time_downstream) - 3 km / (2*time_downstream)

2*Speed_current = (5/2 km)/ time_downstream

2*(3 km/h)= (5/2 km)/ time_downstream

time_downstream = 0.416 h

(Speed_boat + 3km/h) = 4 km / (0.416 h)

Speed_boat = 6.6 km/h

Trip upstream

(Speed_boat - Speed_current) = 10 km / (time_trip)

time_trip = 10 km/(3.6 km/h) = 2.777 h

time_trip = 2.777 h

3 0

3 years ago