The answer you are looking for is associative property of addition.
In associative property, no matter where the parenthesis are, a + (b + c) is going to be equal to (a + b) + c. Since the parenthesis follow the equation a + (b + c) = (a + b) + c, you can assume you are using the associative property. Lastly, add "of addition" to associative property, since you are using addition, not multiplication.
I hope this helps!
For the first example given the answer would be No. you have a 4 mile head start. at the 4 mile line, your friend starts at 8 miles an hour and you start running at 6 miles an hour. basic addition should give the answer. In one hour time, you wouldve ran 6 miles plus the 4 you had as a head start, giving you the 10 miles you needed to reach the finish line. He on the other hand, Biked 8 miles in an hour time. By that time, you had just reached the finish line.
So the answer is no for the first example
For the second example the maths get bit harder. You start at the 5 mile point and you friend starts at the beginning point. You only need 5 miles to win, and your friend needs double (its actually more than double, because if it was perfectly doubled, you would tie the race. Your pace just has to be a bit more than half of his speed. his speed is 17mph. yours, by logic, needs to be even a tad bit more than 8.5mph. You need to have a faster speed than 8.5mph (8.51mph works perfectly) and you win by a hair. But when we se your example, you're only going at 7mph. A whole mile and a half behind pace. Sadly, he passes you short before winning.
The second example is YES he does pass you before the end of the trail.
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Answer:
No
Step-by-step explanation:
This is not an equation since it does not contain an equal (=) sign and instead contains a less than (<) sign making it an inequality.
Answer:
5
Step-by-step explanation:
Answer: C is the correct statement " In ΔADC and ΔBCD AD=BC, opposite sides of a rectangle are congruent"which completes the proof .
Step-by-step explanation:
Given: A figure shows a rectangle ABCD having diagonals AC and DB.
Anastasia wrote the proof given in picture to show that diagonals of rectangle ABCD are congruent.
We can see the Statement 2 which tells that AB=CD, opposite sides of a rectangle are congruent. In Statement 3 she used Pythagoras theorem to show AC²= BD² by using Statement 1 and 2.
Thus we can see she need to introduce two triangles named as ACD and BCD and the remaining sides to write the proof is AD=BC with correct reason i.e. opposite sides of a rectangle are congruent.
Therefore Statement 1 would be In ΔADC and ΔBCD AD=BC, opposite sides of a rectangle are congruent.