Assuming that the container and books are rectangular, the volume of both objects can be computed with the formula V=lwh, where l is length, w is width, and h is height.
As the volume of the container is 1728 m^3, while the volume of each book is 1920 cm^3. The volume for each book is converted to in terms of meters by dividing it with 100^3. The volume for each book after this conversion is 1.92 x 10^-3 m^3.
The number of the books that can fit in the shelf is the volume of the shelf divided by the volume of the books, with the assumption that the books fit perfectly in the shelf.
With the volume of the shelf divided by the volume of the books, 900,000 books can be fitted in the shelf.
Answer: Mural height: 22ft and the Mural width is 10ft
Step-by-step explanation: I took the test and got it wrong, but they told me the correct answers after I took the test. (I got to K-12) Proof:
Answer:
A. False
B. True
C. True
D.True
Step-by-step explanation:
A. False . The significance level or alpha is the probability of rejecting the null hypothesis when it is true. For example, a significance level of 0.05 indicates a 5% risk of concluding that a difference exists when there is no actual difference. 0.01 alpha is better than 0.05 alpha . 0.01 indicate a 1% risk of rejecting the null hypothesis when it is true .
B. True . If the p-value is less than alpha, we reject the null hypothesis . Therefore statistically significant.
C . True . If the p-value is less than alpha, we reject the null hypothesis
D. True . Alpha will be greater than p-value . Therefore we will reject .
Step-by-step explanation:
Since ,
Money lended =$400
Intetest =27.74%
Therefore,
Intetrst=p×r×t/100,if interested monthly
=400×27.74×1/100(interested monthly)
=4×27.74
=$110.96
Interest=p×r×t/100×1/12,if interested anually
=400×27.74×1/100/12
=110.96/12
=$9.24 or it will be $110.96 if it is interested anuaaly..
A confidence interval tells us how many percents we are confident about the range of a parameter. In this problem, <span>a 95% confidence interval for the mean number of hours spent relaxing or pursuing activities they enjoy was (1.38, 1.92). That means we're 95% confident that the Americans spend from 1.38 hours to 1.92 hours per day on average relaxing or pursuing activities they enjoy. In other words, 95% of the samples of the same size would have a mean number of hours relaxing or pursuing activities they enjoy between 1.38 to 1.92.</span>
