Question

Please help. I’ll mark you as brainliest if correct!

Answer 1

Answer:

$a = - \frac{3}{8} \\ \\ b = \frac{1}{8}$

Step-by-step explanation:

$\frac{ - 1 - 3i}{8i} \\ \\ = \frac{ - 1 - 3i}{8i} \times \frac{i}{i} \\ \\ = \frac{( - 1 - 3i)i}{8i \times i} \\ \\ = \frac{ -1 \times i - 3 {i}^{2} }{8 {i}^{2} } \\ \\ = \frac{ - i - 3 ( - 1)}{8 ( - 1) } \\ \\ = \frac{ - i + 3}{ - 8} \\ \\ = \frac{ i - 3}{ 8} \\ \\ = \frac{ - 3 + i}{ 8} \\ \\ = \frac{ - 3}{8} + \frac{i}{8} \\ \\ \purple{ \bold{ = - \frac{3}{8} + \frac{1}{8} i}} \\ equating \: it \: with \: a + bi \\ \\ a = - \frac{3}{8} \\ \\ b = \frac{1}{8}$

Answer 2

Answer:

a= -3/8

b= 1/8

Step-by-step explanation:

To remove i from the denominator, we need to multiply the numerator and denominator by -i

$\frac{(-1-3i)(-i)}{8i(-i)}$

This simplifies to

$\frac{i+3i^{2} }{-8i^{2} }$

This further simplifies to

$\frac{i-3}{8}$

This can be rewritten as

$-\frac{3}{8} +\frac{1}{8} i$

a= -3/8

b= 1/8