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In-s [12.5K]
3 years ago
7

A century year such as 1900, 2000, or 2100 is a leap year only if it is a multiple of 400

Mathematics
1 answer:
blondinia [14]3 years ago
6 0
If this is a true or false question, then the answer is true. This is because we technically have 365.2425 days in a year and if you add an extra day every 4 years, you get an average of 365.25. It is A LOT of math, but even though there was an extra day in 1896 and 1904, there was no leap year in 1900 because of the 400 multiple rule.
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Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
Write a description of -5a + 3 &gt; 1 inequality
Andrej [43]

The sum of -5a and 3 is greater than 1

6 0
2 years ago
What is 9 is 12% of which number???
ASHA 777 [7]
9 is 12% of 75 check it 9* 100 = 900 / 75 = 12
4 0
3 years ago
20 points
never [62]
The answer would be, it was reduced by 35%
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2 years ago
S
Korolek [52]

Answer:

D

Step-by-step explanation:

If its right let me know I think this is right

8 0
3 years ago
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