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VladimirAG [237]
3 years ago
7

yo can someone pls help me with this i’ve been crying for the last hour bc i can’t figure it out and it’s due in 30 minutes. the

question is “find the area and perimeter to this composite figure”. i will give you the most brainly if you answer and solve. thank you <3

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

9514 1404 393

Answer:

  • area: 524 cm²
  • perimeter: 124.8 cm

Step-by-step explanation:

The rectangle in the middle has a width equal to the radius of the semicircular ends, so (20 cm)/2 = 10 cm.

The semicircular ends, together, make a complete circle of radius 10 cm.

The area is the sum of the areas of the parts:

  A = LW = (21 cm)(10 cm) = 210 cm² . . . . . . rectangle area

  A = πr² = π(10 cm)² = 100π cm² ≈ 314 cm² . . . . . circle area

The total area is ...

  210 cm² +314 cm² = 524 cm² . . . . area of the figure

__

The perimeter of the figure is the sum of the lengths of all of the edges. From the left, working clockwise, we have ...

  P = (1/2 circle of diameter 20) + (rectangle top = 21) +(1/2 circle of diameter 20) +(circle radius = 10) +(rectangle bottom = 21) +(circle radius = 10)

The two 1/2 circles add to a whole circle with a circumference of ...

  C = πd = (3.14)(20 cm) = 62.8 cm

Then the whole perimeter is ...

  P = 62.8 cm + 21 cm + 10 cm + 21 cm + 10 cm = 124.8 cm

_____

Note that we have used 3.14 for pi. If you use a more exact value, your answers will be slightly different.

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Answer:

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2. Rolling a 2

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4 0
3 years ago
A garden in the shape of a rectangle a 140 feet long and 95 feet wide.what is the distance around the garden
Tamiku [17]
140 + 140 + 95 + 95 = 470 feet

Hope this helps!
3 0
2 years ago
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Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per
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Answer: (0.8115, 0.8645)

Step-by-step explanation:

Let p be the proportion of people who leave one space after a period.

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Number of people responded that they leave one space. =440

i.e. sample proportion: \hat{p}=\dfrac{440}{525}\approx0.838

z-score for 90% confidence level : 1.645

Formula to find the confidence interval :

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

0.838\pm (1.645)\sqrt{\dfrac{0.838(1-0.838)}{525}}\\\\=0.838\pm (1.645)\sqrt{0.00025858285}\\\\=0.838\pm (1.645)(0.01608)\\\\= 0.838\pm0.0265\\\\=(0.838-0.0265,\ 0.838+0.0265)\\\\=(0.8115,\ 0.8645)

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