4x+6+3=17
4x+9(add the 6 and 3)=17
4x=8(subtract 9 from each side 4x+9-9=17-9)
x=2(divide each side by 4, 4x/4=8/4)
2 is the final answer.
You can check your work...
4(2)+6+3=17
8+6+3=17
14+3=17
17=17
So this is correct!!! Hope this helps you.
Answer:
![15.2+2w\leq 28](https://tex.z-dn.net/?f=15.2%2B2w%5Cleq%2028)
Step-by-step explanation:
Let w represent width of the rope-off section.
We have been given that a manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope.
We will use perimeter of rectangle formula to solve our given problem. We know that perimeter of a rectangle is equal to 2 times the sum of length and width.
![\text{Perimeter}=2l+2w](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%7D%3D2l%2B2w)
Upon substituting our given values, we will get:
![\text{Perimeter}=2(7.6)+2w\\\\\text{Perimeter}=15.2+2w](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%7D%3D2%287.6%29%2B2w%5C%5C%5C%5C%5Ctext%7BPerimeter%7D%3D15.2%2B2w)
Since the manager can use no more than 28 m of the rope, so perimeter of rope-off section should be less than or equal to 28 meters.
We can represent this information in an inequality as:
![15.2+2w\leq 28](https://tex.z-dn.net/?f=15.2%2B2w%5Cleq%2028)
Therefore, our required inequality would be
.
Let us find width as:
![15.2-15.2+2w\leq 28-15.2](https://tex.z-dn.net/?f=15.2-15.2%2B2w%5Cleq%2028-15.2)
![2w\leq 12.8](https://tex.z-dn.net/?f=2w%5Cleq%2012.8)
![\frac{2w}{2}\leq \frac{12.8}{2}\\\\w\leq6.4](https://tex.z-dn.net/?f=%5Cfrac%7B2w%7D%7B2%7D%5Cleq%20%5Cfrac%7B12.8%7D%7B2%7D%5C%5C%5C%5Cw%5Cleq6.4)
Therefore, the width of the rope-off section should be less than or equal to 6.4 meters.
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Answer:
Finding the square root of a number is the inverse operation of squaring that number. Remember, the square of a number is that number times itself.