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stellarik [79]
3 years ago
7

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar

e true? Check all that apply.
7 x + 4 and 3 x + 5 + 4 x minus 1
When x = 2, both expressions have a value of 18.
The expressions are only equivalent for x = 4 and x = 6.
The expressions are only equivalent when evaluated with even values.
The expressions have equivalent values for any value of x.
The expressions should have been evaluated with one odd value and one even value.
When x = 0, the first expression has a value of 4 and the second expression has a value of 5.
The expressions have equivalent values if x = 8.
Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

first and third

Step-by-step explanation:

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5 0
3 years ago
Mr. Mendoza invests in five stocks. The table shows the growth in stock prices in dollars at the end of a trading day.
Morgarella [4.7K]

Answer:

The correct answer is C, as growth on stock E is bigger from the growth of stock B

Step-by-step explanation:

In order to resolve this problem, we must have in mind that the negative numbers are smaller when they are more distant from 0, and that positive numbers are bigger when they are more distant from 0. So, the biggest number of growth is the one that is more distant from 0.

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3 years ago
Read 2 more answers
Prove sin^2 theta-sin^2 theta is sin tetha sin 3 theta<br><br>how to prove..pls help!! thanksss
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3 0
2 years ago
Express<br><br> 2x^2+3x/(2x+3)(x-2) - 6/x^2-x-2 <br><br> As a single fraction in its simplest form.
Dmitry [639]

Answer:

(x + 3)/(x + 1) .

Step-by-step explanation:

2x^2 + 3x/(2x + 3)(x - 2) - 6 /x^2 - x - 2

= 2x^2 + 3x/(2x + 3)(x - 2) - 6 / (x - 2)(x + 1)

The LCM is (2x + 3)(x - 2)(x + 1) so we have

(2x^2 + 3x)(x + 1) - 6(2x + 3)          x( 2x + 3)(x + 1) - 6(2x + 3)

--------------------------------------- =        ------------------------------------

    (2x + 3)(x - 2)(x + 1)                         (2x + 3)(x - 2)(x + 1)


       (2x + 3)(x(x + 1) - 6)           (2x + 3)(x - 2)(x + 3)

=    ----------------------------  =       ---------------------------     =  (x + 3)/(x + 1)

     (2x + 3)(x - 2)(x + 1)             (2x + 3)(x - 2)(x + 1)  

7 0
3 years ago
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