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mart [117]
3 years ago
12

What is the solution to 2x-y=1 Зу + 3 = 6x Using system of equations

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

infinitely many solutions

Step-by-step explanation:

Reduce the second equation by dividing all three terms by 3:  y + 1 = 2x.  Then compare this result to the first equation 2x - y = 1.  Noe that these two equations are identical.  Thus, the two lines coincide.  There are "infinitely many solutions."

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Write a cosine function that has a midline of 2, an amplitude of 4 and a period of 4/7
ella [17]

Answer:

y= 4cos(\frac{7\pi }{2}x)+2

Step-by-step explanation:

We know that the transformations of a cosine equation can be shown as:

y=±a(b(x-h))+k

Where 'a' is the amplitude

'b' is the horizontal change (Do 2π/b to find the period)

'h' is the horizontal shift

and 'k' is the vertical shift or midline.

------------------------------------------------------

If the amplitude is 4, we can assume a=4.

Since the period is 4/7, we can solve for the 'b' value by:

2\pi /\frac{4}{7}= \frac{7\pi }{2}

Next, since the midline is 2, we know that a vertical shift of 2 occurred. Thus, the 'k' value is 2.

Writing this equation gives us:

y= 4cos(\frac{7\pi }{2}x)+2

4 0
4 years ago
Which of the following is equivalent to the polynomial given below?
Marizza181 [45]

Answer:

(x+(3+\sqrt{11}i)) (x+(3-\sqrt{11}i))

Step-by-step explanation:

The first step to this problem is to look at the key features of the initial expression given to us. Namely, the middle term.

Notice that it is just +6x. This indicates that the square root terms cancel out, meaning that their signs need to be opposite, but the threes need to have the same, positive sign. This indicates that our answer is option C, but you should always double check by multiplying the expression out to confirm. Here are the steps:

(x+(3+\sqrt{11}i)) (x+(3-\sqrt{11}i))

x^{2} +(3+\sqrt{11}i)x+(3-\sqrt{11}i)x+(3+\sqrt{11}i)(3-\sqrt{11}i)x^{2}+3x+\sqrt{11}ix+3x-\sqrt{11}ix+9+3\sqrt{11}i-3\sqrt{11}i-(\sqrt{11})^{2}(i^{2})x^{2}+6x+9-(11)(-1)

x^{2}+6x+9+11

x^{2}+6x+20

Therefore as we suspected, the answer is C.

3 0
3 years ago
Give the general form of the equation of the line through (1,2) and is perpendicular to the line passing through (-6,-3)(6,3)
olga nikolaevna [1]

Answer:

4x+3y-10=0

Step-by-step explanation:

first find the gradient of the line that is perpendicular to the line of interest.

y2-y1/x2-x1

3--3/6--6

=3+3/6+6

=9/12

3/4

The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is -4/3

next, substitute information into

y-y1=m(x-x1)

y-2=-4/3 (x-1)

multiply both sides of equation by 3

3y-6=-4 (x-1)

expand brackets

3y-6=-4x+4

rearrange in general form

4x+3y-10=0

6 0
3 years ago
What is the slope of the line that is perpendicular to the line whose equation is 2x+y=4??
zmey [24]

Answer:

The slope would be 1/2

Step-by-step explanation:

y= mx +b

m= slope

perpendicular lines have slopes that are multiplied in order to get -1

<em>these are important</em>

<em></em>

2x + y = 4

<u><em>subtract 2x</em></u>

y=-2x +4

your slope is -2

-2 * ? = -1

? = -1/-2

? = 1/2

6 0
3 years ago
I know it has to be a negative...........
sleet_krkn [62]

Answer:

m=-3

Step-by-step explanation:

  1. Choose 2 points on the graph. (-2,8) (3,-7)
  2. Apply slope formula.

m=\frac{rise}{run} =\frac{y2-y1}{x2-x1} \\\\\frac{-7-(8)}{3-(-2)} = \frac{-15}{3} =-3\\\\m=-3

I hope I choose the right cordinates...

4 0
4 years ago
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