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Semmy [17]
3 years ago
11

The volume of paint used, V liters, is directly proportional to the area, A square feet, that the paint can cover. 5 liters of p

aint can cover a wall with an area of 75 square feet.
Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

<u>Question Completion</u>

a) Find the constant of proportionality.

b) Write an equation relating V and A.

c) How much paint would be needed to cover an area of 180 square feet? Answer:

(a)k=\frac{1}{15} \\\\(b)V=\frac{1}{15}A

(c)12 Liters

Step-by-step explanation:

The volume of paint used, V liters, is directly proportional to the area, A square feet, that the paint can cover.

This is written as:

V \propto A\\V=kA,$ where k is the constant of proportionality

(a)5 liters of paint can cover a wall with an area of 75 square feet.

V=5 liters, A=75 square feet.

Substitution into V=kA

5=75k

k=5/75

\text{Constant of proportionality, k}=\dfrac{1}{15}

(b)Substitution of k=\dfrac{1}{15} into V=kA

The equation relating V and A is:

V=\frac{1}{15}A

(c)If A=180 Square feet

Volume of paint needed,

V=\frac{1}{15} X 180\\=12$ liters

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

      P(U |D ) = 0.198

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Step-by-step explanation:

The total number of deaths is mathematically represented as

      T   =  16 +  23 + \cdots  +  16

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The total number of deaths in 1996 - 2000 is mathematically represented as

     T_a =  16 +  23+ \cdots + 30

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The total number of deaths in 2001 - 2005 is mathematically represented as

     T_b =  17 +  16 + \cdots + 23

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The total number of deaths in 2006 - 2010 is mathematically represented as

     T_c =  15 +  17 + \cdots + 16

      T_d = 182

Generally the the probability that it would occur under the tree given that the death was  after  2000 is mathematically represented as

     P(U |D ) = \frac{P(A \ n\  U )}{P(A)}

Here  P(A \ n\  U ) represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

         P(A \ n\  U )   = \frac{Z}{ T}

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         Z =  35 +  42

=>       Z =  77

=>       P(A \ n\  U )   = \frac{77}{ 623}

=>      

Also

     P(A) is the probability of the death occurring after 2000  and this is mathematically represented as

        P(A) =  \frac{T_b  +  T_c}{ T}

=>      P(A) =  \frac{ 206+  182}{623}

=>  

So

         P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+  182}{623}}

=>      P(U |D ) = 0.198

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      P(O | B) = \frac{T_z}{ T}

Here T_z is the total number of death outside / camping before 2001  and the value is  117  

So

            P(O \ n \ B) = \frac{117}{623}

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          P(B ) =  \frac{T_a}{T}

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So

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=>       P(O | B) =   0.498

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