Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
The expression would be:
3x
x=number of plays
Insert 4:
3(4)
=12
They would 12 yards after 4 plays if losing 3 yards every play.
Answer:
honors
Step-by-step explanation:
And what else you can not solve that problem
Hold on i believe its C but let me go look on google and i'll get back to you to sure
