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Natasha2012 [34]
3 years ago
15

write an expression in simplest form that represents the total amount in each situation: Today is your friends birthday. she is

y years old. her brother is 5 years younger.​
Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

2y-5

Step-by-step explanation:

friend: y

Brother: y-5

y+y-5

aka

2y-5

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Help please! Its late! Xoxo
Mrrafil [7]

Answer:

1)B

Step-by-step explanation:

4 0
3 years ago
a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

3 0
3 years ago
Help Pls! I need this fast!
lesya [120]

Answer: 36

Step-by-step explanation:

\overline{AB} \cong \overline{BC} (Triangle ABC is isosceles)

m\angle CAB=m\angle CBA=30^{\circ} (base angles of an isosceles triangle are congruent)

\angle MCB=90^{\circ} (In triangle CMB, angles in a triangle add to 180 degrees)

\angle ACM=30^{\circ} (triangle sum theorem)

MB=24 (30-60-90 triangle CMB)

AB=12 (sides opposite congruent angles in a triangle are congruent)

AB=36 (segment addition postulate)

3 0
2 years ago
Find the lowest common denominator. 1/(x+2)^2, 1/(x-2)^2, 2/(x^2-4) A. (x+2)^2 (x-2)^2 B. (x^2+2) (x^2-2)
klasskru [66]

Answer:

(x + 2) ^2 (x - 2) ^ 2 so A is the answer.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30                                   =-6(5)

b=-1                                          =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0
3 years ago
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