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likoan [24]
2 years ago
10

УА

Mathematics
1 answer:
NemiM [27]2 years ago
4 0
H:0,7
J:1,0
F:3,3
E:5,7
G:7,2
K:8,5
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Identify the lateral area and surface area of a regular square pyramid with base edge length 5 in. and slant height 9 in.
Galina-37 [17]
Note that a squared pyramid has a square base & 4 equal triangles.
To find the lateral the lateral area you calculate the area of the 4 equal triangles  and to find the surface area (total Area) you add the area of the base:

Area of each triangle = side (5) x slant (9) and you divide by 2

==>Aera of 1 triangle = (9x5)/2 = 45/2 & for the 4 triangles

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Now the base area (square) = 5 x 5= 25 in²

so the surface area = 90+25 = 115 in² (answer a)
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