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Alex73 [517]
3 years ago
11

How to write b^1/4 in radical from

Mathematics
2 answers:
Svetlanka [38]3 years ago
7 0

Answer:

Me too I find difficulties in it

Step-by-step explanation:

Please get the right answer please

MA_775_DIABLO [31]3 years ago
5 0

Answer:

\sqrt[4]{b}

Step-by-step explanation:

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Answer:

It is (B) ED2021

Explanatory variable: time spent streaming videos

Response variable: time spent exercising

4 0
3 years ago
6. Find the value of y.<br> 5<br> 16
Svetllana [295]
3.59999
or 3.6
hopefully this helps you!
4 0
3 years ago
What Are some ways to describe rhe relationships between sets of Numbers?
vagabundo [1.1K]
<span>We can have the basic inequalities and equalities’ sign. (>, =, <). </span>
<span>These three set of symbols can discern, describe and explain the relationship between of numbers. These signs are used varying in many mathematical operations to explain and find discrepancy between value, sets of values or numbers in single and equitable category. </span>
Examples includes
 6 > 5; 6 is greater than 5; 5 is less than 6
<span> 1 > -1; -1 is less than 1; 1 is greater than -1 </span>
<span>-2 = -2; -2 is equal to -2  <span> </span></span>

7 0
3 years ago
What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

y'=Py+Qy^n
y^{-n}y'=Py^{1-n}+Q

and substitute v=y^{1-n}. This makes v'=(1-n)y^{-n}y', so the ODE is rewritten as

\dfrac1{1-n}v'=Pv+Q

and the equation is now linear in v.

The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
3 0
3 years ago
Simplify 315/10 <br><br> Fastttt pleaseeeee
Lunna [17]

Answer:

63/2

Step-by-step explanation:

divide by five which is the greatest common factor 315/10÷5

63/5

7 0
3 years ago
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