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2 years ago

An athlete is tracking his weight

Mathematics

2 answers:

ycow [4]2 years ago

7 0

Answer:

His rate of change is 7 pounds per week.

Step-by-step explanation:

Rate of change = change in weight ÷ change in time

change in weight = 188 - 167 = 21 pounds

change in time = 6 - 3 = 3 weeks

Rate of change = 21 ÷ 3 = 7 pounds/week

blsea [12.9K]2 years ago

7 0

Answer:

He loses 7 pounds per week

Step-by-step explanation:

After 3 weeks he weighs 188 pounds.

After 6 weeks he weighs 167 pounds.

Weight loss = (188 - 167) pounds = 21 pounds

Time interval = 6 weeks - 3 weeks = 3 weeks

Rate of change = Weight loss ÷ time interval = $\frac{21}{3}$ pounds per week = 7 pounds loss per week.

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Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

Please help 50 points!<br> Simplify the expressed

LenKa [72]

Answer:

Step-by-step explanation:

$\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}$ rewrite as multiplication

$\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}$ look to factor

$\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}$ , difference of 2 squares and perfect square

$\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}$ , finish factoring and simplify

2(x+3)

3 0

2 years ago

Round the following to the nearest cent: $16.997

Paul [167]

$\$16.99\underbrace{7}_{>5}\approx\$17.00$

7 0

2 years ago

Please someone help quickly thank you very much

Tema [17]

Answer:

I think the answer is 81.

Step-by-step explanation:

Vertical angles are congruent.

x + 3 = 84

- 3 = -3

--------------

x = 81

3 0

3 years ago

If you reflect the image over the x - axis, what are the new coordinates of the shape?

lutik1710 [3]

Greetings!

When reflecting a shape over the x-axis, you simply change the number to its opposite positive/negative equivalent.

This means that the new co-ordinates would be (-5,1) , (-5,4) and (-2,4).

Hope this helps!

8 0

3 years ago