3.22 divided by 14 is .23. .23 plus .15 is .38 cents per candy at regular price.
Option C is your answer.
It's a negative sloping line which eliminates A and D. Then you just do the whole rise-over-run deal to get the 3/4 part.
We know that 3/10*20=6 students are eating salads.
We also know that 3/5*20=12 students are eating sandwiches.
Assuming each person only eats one thing, there are 20-12-6=2 students eating lunches other than salads or sandwiches.
This would mean that she has been in school for about 1,000 days. Thus, we need to figure out the amount of days she would have went to school within the week. This would normally be 5 days within the 7.
5/100 x 1000 is 714.28
When rounded to the nearest ten, it would end up at 710.
Answer:
hope this help good luck
Step-by-step explanation:
a. H0: μ = 26.6
b. Ha: μ > 26.6
c. Let x = the mean age for online students at De Anza College.
d. Student’s t-distribution
e. 9.98
f. p-value = 0.0000
g. Check student’s solution.
h. i. Alpha: 0.01
ii. Decision: Reject the null hypothesis.
iii. Reason for decision: The p-value is less than 0.01.
iv. There is sufficient evidence to conclude that the mean age of online students at De Anza College is greater than 26.6 years.i. (28.8, 30.0)
