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zhuklara [117]
1 year ago
10

Drag and drop an answer to each box to correctly complete the explanation for deriving the formula for the volume of a sphere

Mathematics
1 answer:
denis-greek [22]1 year ago
5 0

The answers that would fill in the blanks are

  • 2r
  • a circle
  • an annulus
  • 1/3πr³
  • 4/3πr³
<h3>What is the Cavalier's principle?</h3>

This principle states that if two solids are of equal altitude then the sections that the planes would make would have to be parallel and also be at the same distances from their bases which are equal such that the volumes of the solids would be equal.

Now we have to fill in the blanks with the solution.

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius r and height<u> 2r</u> minus the volume of two cones, each with a radius and height of r. A cross section of the sphere is a <u>circle</u> base of cylinder, is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is an <u>annulus_ </u>.The volume of the cylinder with radius r and height 2r is 2πr³, and the volume of each cone with radius r and height r is 1/3πr³. So the volume of the cylinder minus the two cones is 4/3πr³. Therefore, the volume of the sphere is by Cavalieri's principle

Read more on Cavalieri's principle here

brainly.com/question/22431955

#SPJ1

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Find two integers whose sum is -8 and product is -48
fomenos

Answer:

-12 and 4

Step-by-step explanation:

-12+4=-8

(-12)*4= -48

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Draw a square that has a circumference of 12 cm.
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a square has four equal sides so 12 ÷ 4 = 3, so each side is 3 then, 3+3+3+3 = perimeter.

check the picture below.

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As a 7 1/4 inch candle burns down, its height we decreases three-quarter inch inch each hour. How many hours does it take for th
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3.201 in expanded form
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Heya!

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3 years ago
Read 2 more answers
What is the center of a circle whose equation is x2 y2 – 12x – 2y 12 = 0? (–12, –2) (–6, –1) (6, 1) (12, 2)
lora16 [44]

The center of a circle whose equation is x^2 +y^2 – 12x – 2y  +12 = 0 is (6,1)

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as:

x^2 + y^2 + 2gx + 2fy + c = 0

where:

(-g, -f) is the centre of the circle

Given the equations

x^2 +y^2 – 12x – 2y  +12 = 0

Compare

2gx = -12x

g = -6

Simiarly

-2y = 2fy

f = -1

Centre = (6, 1)

Hence the  center of a circle whose equation is x^2 +y^2 – 12x – 2y  +12 = 0 is (6,1)

Learn more on equation of a circle here: brainly.com/question/1506955

8 0
2 years ago
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