1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
3 years ago
6

I need help in this question can anyone help me please. A pattern has 4 blue triangles to every 12 yellow triangles. If you were

to draw 16 blue triangles, how many yellow triangles would you need?
Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

48 yellow triangles

Step-by-step explanation:

this problem can be represented as a ratio

4b : 12y (4 blue to 12 yellow)

16 blue triangles is 4 more time the amount than the original ratio.

16b : ?y

you can solve this problem by multiplying 12 by 4

12 * 4 = 48

this now means that for the 16 blue triangles, there should be 48 yellow.

16b : 48y

i hope this makes sense to you, and i was helpful.

stay safe!!

:)

You might be interested in
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
2 years ago
HELPPPP PLEASE IN NEED HELP FAST I NEED ALL 5 DONE
Radda [10]

1. 11h

2. 10w

3. 6w

4.6 (h+3)

5. 74

hope it's helpful.

6 0
3 years ago
House B is a reflection of House A.
Luden [163]

Answer:add all them up !

Step-by-step explanation:

8 0
3 years ago
Casey can do 4 math problems in 13 minutes. How many can he do in 7 minutes?​
mojhsa [17]

Answer:

2.15384615385

Step-by-step explanation:

8 0
2 years ago
Suppose the scale factor you will use to enlarge the map is 5:1. What is the approximate area of the park in your enlarged drawi
slamgirl [31]

Answer:

525

Step-by-step explanation:

If the area of the map is 21 and the scale factor is 5:1, both of the dimensions of the flat park are multiplied by 5. If both dimensions are multiplied by 5, then the area is multiplied by (5*5)=25 times. 25*21=525. Hope this helps!

4 0
3 years ago
Other questions:
  • An integer x is divided by an integer y, and quotient is 24.the sum of these two integers is 75. what is the value of x?
    6·1 answer
  • You and your friend are selling tickets for the orchestra concert. OnThursday, you sold 15 tickets and your friend sold 10 ticke
    13·1 answer
  • Which of the following is the graph of the inequality y&lt; -2x + 3?
    8·1 answer
  • What is 10 more than 124
    7·2 answers
  • A major purpose of preparing closing entries is to a) adjust the asset accounts to their correct current balances. b) update the
    14·1 answer
  • Solve the compound inequality 6b &lt; 42 or 4b + 12 &gt; 8
    10·1 answer
  • Please help do this right aswer gets brain liest
    11·2 answers
  • How to solve this? Is the question correct? ty :)
    14·1 answer
  • Question 8<br> Show the work please
    6·1 answer
  • The table shows the points Isabella scored during each basketball game of her regular season.
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!