1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
earnstyle [38]
3 years ago
6

Which of the functions below could have created this graph?

Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

i don't know if this is right or not i did to much work to put it all down but i pretty sure it's C.

You might be interested in
I need help asparagus is it a b c d please help me
Yuri [45]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
J1, J2 and J3 are three junctions on a motorway. The distance from J2 to J3 is 8.7 miles. The distance from J1 to J2 is one-thir
leonid [27]

Answer:

11.6 miles

Step-by-step explanation:

Given that:

Distance from J2 to J3 = 8.7 miles

Distance between J1 and J2 = 1/3 of J2 toJ3

Hence, distance between J1 and J2 becomes :

1/3 * 8.7 miles = 2.9 miles

Distance from J1 to J3 equals :

(J1 to J2) + (J2 to J3)

2.9 miles + 8.7 miles

= 11.6 miles

5 0
3 years ago
Write an equation for the nth term of the arithmetic sequence. Then find a50.
julia-pushkina [17]

Step-by-step explanation:

Since the sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1/3

d = 1/2 - 1/3 = 1/6 or 2/3 - 1/2 = 1/6

Substitute the values into the above formula

That's

<h3>A(n) =  \frac{1}{3}  + (n - 1) \frac{1}{6}  \\  =  \frac{1}{ 3}  -  \frac{1}{6}   +  \frac{1}{6} n</h3>

So the nth term of the sequence is

<h3>A(n) =  \frac{1}{6}  +  \frac{1}{6}n</h3>

For a50 since we are finding the 50th term

n = 50

So we have

<h3>A(50) =  \frac{1}{6}  +  \frac{1}{6} (50) \\  =  \frac{1}{6}  +  \frac{25}{3}</h3>

We have the final answer as

<h3>A(50) =  \frac{17}{2}</h3>

Hope this helps you

4 0
3 years ago
Kurt's truck uses 12 gallons of gas to travel 144 miles. He has 6 gallons in the tank. How much more gas will he need to drive 3
LenKa [72]
I hope this helps you



12 gallons for 144 miles


6 galoons for 144/2=72 miles


1 gallon for 72/6=12 miles


if 1 gallon for 12 miles


how many gallons for 324 miles


?.12=1.324


?=324/12


?=27 miles
8 0
3 years ago
Two percent of Jennie’s skin cells were burned when she escaped from a fire. If 3.7×10^10 of her skin cells were burned then, ho
gulaghasi [49]

1813\times10^9 cells were not burnt when Jennie escaped from the fire.

<u>Solution:</u>

Given:

2% of skin cells were burnt i.e, 3.7\times10^{10} of skin cells were burnt.

To find:

Number of skin cells that were not burnt

We can write 3.7\times10^{10} \text{ as } 37\times10^{9}

Therefore, by equating the values we get,

2% of the cell is 37\times10^9

1% of the cell is \frac{37\times10^9}{3}=18.5\times10^9

As, 1% of the cell is 18.5\times10^9

98%  of the cell will be 98\times18.5\times10^9=1813\times10^9

\therefore \text{ skin cells that are not burnt is } 1813\times10^9

8 0
3 years ago
Other questions:
  • If p is prime and n is even such as that p+n =47 and p×n=210 what is the value of n?
    9·1 answer
  • Given x=-3, y=6, and z=-4 xz/-2y
    8·2 answers
  • A random number generator is used to create a list of 300 single-digit numbers. Of those 300 numbers, 146 are odd and 154 are ev
    8·2 answers
  • What is the difference of 17 7/8-12 3/12
    11·2 answers
  • Please help me on this one
    6·1 answer
  • Can someone tell me whats1+1​
    8·2 answers
  • A teacher has found that the probability that a student studies for a test is 0.610.61​, and the probability that a student gets
    5·1 answer
  • Im looking for a man <br> that like to eat
    14·1 answer
  • Please help me with this plssss
    15·2 answers
  • 2x+3y=9<br> 2x+y=7<br> simultaneous equation
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!