1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marta_Voda [28]
3 years ago
10

Erin had 55 stuffed bears. She took out her favorite 7 bears and then equally divided the other bears among her 3 sister. Erin’s

youngest sister, su, already had 15 stuffed bears. How many stuffed bears does su have now?
Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

Su has 17 bears

Step-by-step explanation:

Su has 15, Erin takes out 7 of her collection and splits evenly. each sister should get 2 each. Su has 17.

You might be interested in
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
By the square property, if b is a real number , and a2=b, then a=
Serggg [28]

Answer:

a=\sqrt{6},\:a=-\sqrt{6}

Step-by-step explanation:

Given

  • b is a real number
  • a^2=b

as

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

so

a^2=6

a=\sqrt{b},\:a=-\sqrt{b}

Therefore,

a=\sqrt{6},\:a=-\sqrt{6}

5 0
3 years ago
Read 2 more answers
A theater sells tickets for a concert. Tickets for lower-level seats sell for $35 each, and tickets for upper-level seats sell f
Naya [18.7K]
A*25+b*35=10250
a      +b     = 350         | * -25

25a    + 35b= 10. 250
-25a    -25 b=  -8.750
------------------------------
            10b = 1500
            b=1500:10
             b=150  tickets cost 35 $
           
a= 350-150
            a= 200 tickets cost 25 $
8 0
3 years ago
Read 2 more answers
The price of an item has been reduced by 35%. The original price was $60. What is the price of the item now ?
Lunna [17]

Answer:

the answer is $39.00

Step-by-step explanation:

5 0
3 years ago
The sum of the squares of 2 consecutive negative integers is 41. what are the numbers?
Oliga [24]
The answer is 4 and 5 my dude ( 16 and 25)
8 0
3 years ago
Other questions:
  • If a cell phone costs $225 and the accessories cost 13% of the cell phone price what is the cost of the accessories
    6·1 answer
  • Find the general solution: y''-2y'-3y=-3te^(-t)
    12·1 answer
  • 2/7m-1/7=3/14<br><br> Please solve showing work
    10·2 answers
  • A standard six-sided die is rolled $6$ times. You are told that among the rolls, there was one $1,$ two $2$'s, and three $3$'s.
    13·1 answer
  • Find the height of ABD
    9·1 answer
  • Sal knows the volume of a cylinder is 500 cubic units. He wants to create a cylinder with twice the volume. Which variation of t
    8·2 answers
  • Hector has a bag of colored candies with the following colors: 12 orange, 4 yellow, 10 green, 4 red, 8 blue, 7 purple, and 11 pi
    9·2 answers
  • HELPPPPPPPP DUE TODAYYYY!!!!!!!!!!!!! WORTH 30 POINTS!!!!!!!!!
    11·1 answer
  • Please help I need this
    9·1 answer
  • Select the action you would use to solve 4x = 16. Then select the property that justifies that action.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!