The answer to this problem is b.
First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Answer:
A). Options (C) and (E)
B). 4.8 times
Step-by-step explanation:
Part A
Volume of cylinder (1) = πr²h
= π(6)²(5)
= 565.5 cubic inches
Volume of cone (1) = 
= 
= 188.5 cubic inches
Volume of cylinder (2) = πr²h
= π(6)²(15)
= 1696.5 cubic inches
Volume of cone (2) = 
= 
= 565.5 cubic inches
Volume of sphere = 
= 
= 904.8 cubic inches
Figure having volume greater than 600 cubic inches are cylinder (2) and sphere.
Options (C) and (E) are the correct options.
Part (B)
= 
Therefore, volume of sphere is 4.8 times the volume of cone (1).
Answer: 52:3
Step-by-step explanation:
260 divided by 5 = 52
15 divided by 5 = 3
260:15 = 52:3