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elena-s [515]
2 years ago
5

Line A is perpendicular to Line B.

Mathematics
2 answers:
snow_lady [41]2 years ago
6 0

Answer:

5/8

Step-by-step explanation:

Sergio039 [100]2 years ago
6 0
Answer: 5/8

Did the quiz
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TJ's Cat Food plans to use tins that are the shape of cylinders. Find the height of the tin, if its bottom diameter is 12 cm and
Fynjy0 [20]

Answer:

6.69 cm

Step-by-step explanation:

Given data

Diameter= 12cm

Radius= 6cm

Volume= 757.36cm^3

The expression for the volume of a cylinder is

V= πr^2h

Substitute

757.36= 3.142*6^2*h

757.36=113.112h

h= 757.36/113.112

h= 6.69 cm

7 0
3 years ago
How do I solve -2(x+1)=-8x+1
mylen [45]
-2 (x+1)= -8x+1
-2x-2= -8x+1
+2x. +2x
-2= -6x+1
-1. -1
-3= -6x
÷-6
x=.5

X=0.5
4 0
3 years ago
The probability of winning a raffle is 2/5. What is the probability of not winning the raffle?
Karo-lina-s [1.5K]

Answer:

3/5

Step-by-step explanation:

the probability of winning + probability of not winning must = 1

these are the only 2 options

2/5 + not winning = 1

subtract 2/5 from each side

not winning = 5/5-2/5

not winning = 3/5

5 0
3 years ago
Read 2 more answers
Find the indicated term of the given geometric sequence a1=-20, r=11, n=12
Sphinxa [80]

The first term of this sequence is -20, and the common ratio is 11. Thus, the formula for the nth term is

a(n) = a(1)*(11)^(n-1), or (-20)*(11)^(n-1).

Thus, the 12th term is

a(12) = (-20)*(11)^(12-1) = -20(11)^11 = -20(2.85 times 10 to the 11th power.

or ... -5.71 times 10 to the 12th power.

4 0
3 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
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