Question

Please help me with this answer

Answer 1

Answer:

Step-by-step explanation:

sin^2x=1/2

so sinx=1/V2=V2/2

x=pi/4

Answer 2

Answer:

$\dfrac{\pi}{4},\dfrac{3\pi}{4}$

Step-by-step explanation:

$2\sin^2(\theta)=1$

Divide both sides by 2:

$\sin^2(\theta)=\dfrac{1}{2}$

Take the square root of both sides:

$\sin(\theta)=\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}$

The only two places on the unit circle where the y value of the point is $\dfrac{\sqrt{2}}{2}$ are at:

$\dfrac{\pi}{4},\dfrac{3\pi}{4}$

Hope this helps!