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2 years ago

What is the answer for x\6=5

2 answers:

7 0

Multiply each side of the equation by 6
and the answer jumps out at you.
(If you don't get 30, go back and check your work.)

Olegator [25]2 years ago

7 0

$\frac{x}{6}=5\ \ \ \ |multiply\ both\ sides\ by\ 6\\\\\not6^1\cdot\frac{x}{\not6_1}=6\cdot5\\\\\boxed{x=30}$

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In the given figure we can determine the coordinate of point M from the graph, we get:

$M=(\frac{d}{2},\frac{c}{2})$

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$N=(\frac{a+b}{2},\frac{c}{2})$

Now, to determine the length of segment MN, we need to subtract the x-coordinate of M from the coordinates of N, we get:

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Subtracting the fractions we get:

$MN=\frac{a+b-d}{2}$

Now, to obtain the length of AB we need to subtract the x-coordinate of A from the x-coordinate of B.

The coordinates of A are determined from the graph:

$A=(0,0)$

The coordinates of B are:

$B=(a,0)$

Therefore, the length of segment AB is:

$AB=a$

Now we do the same procedure to determine the segment of CD. The coordinates of C are:

$C=(b,c)$

The coordinates of D are:

$D=(d,c)$

Therefore, CD is:

$CD=b-d$

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1 year ago

A mirror is 24 inches high and 28 inches wide. The center of the mirror will hang 514 feet from the floor on a wall that is 8 fe

Vanyuwa [196]

The distance from the top of the mirror to the ceiling once the mirror is hung on the wall is 21 inches

The dimension of the mirror is given as:

$Height = 24\ in$

$Width = 28\ in$

From the center of the mirror to the floor of the wall, the distance is:

$Distance =5\frac14\ ft$

So, the distance to the top of the mirror will be:

$Top = 5\frac 14\ ft + \frac 12 \times Height$

Substitute 24 for height

$Top = 5\frac 14\ ft+ \frac 12 \times 24\ in$

$Top = 5\frac 14\ ft+ 12 \ in$

Convert feet to inches

$Top = 5\frac 14\times 12\ in+ 12 \ in$

$Top = 63\ in+ 12 \ in$

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The distance from the top of the mirror to the ceiling is the difference between the height of the wall and 75 inches.

So, we have:

$Distance = 8\ ft - 75\ in$

Convert feet to inches

$Distance = 8\times 12\ in - 75\ in$

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$Distance = 21\ in$

Hence, the distance is 21 inches