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dybincka [34]
3 years ago
10

A community swimming pool is a rectangular prism that is 30 feet long, 12 feet wide, and 5 feet deep. The wading pool is half as

long, half as deep, and the same width as the larger pool.
How many times greater is the volume of the swimming pool than the volume of the wading pool?
Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0
The correct answer is 1,350
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If a quantity increases by 25% and then decreases by 25%, will that result be the original quantity? Explain.
alexandr1967 [171]
<span>If a quantity increases by 25% and then decreases by 25%, will that result be the original quantity? Explain.
Let’s try to be able to know the answer:
=> Let’s have 10 as the value
Increase by 25%
=> 10 + 25%
=> 10 * .25 =  2.5
=> 10 + 2.5 = 12.5 the new value
Now, decrease this by 25%
=> 12.5 – 25%
=> 12.5 * .25 = 3.125
=> 12.5 – 3.125 = 9.375 or 9.4
Thus, the given statement is false.

</span>



3 0
3 years ago
Anthony, William, Christopher and Mathew are sharing 4 hats: red, green blue and gold. If Anthony doesn't wear red, william does
pogonyaev
3 ways
1st way: Anthony- Gold William-Red Christopher-Green Mathew-Blue

2nd way: Anthony- Blue William-Gold Christopher-Red Mathew-Green

3rd way: Anthony-Green William-Blue Christopher-Gold Mathew-Red
7 0
2 years ago
(2a-4a2+8)+(5a2 -5a+6)
lana [24]
A^2-3a+14 is the answer :)
8 0
2 years ago
Read 2 more answers
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
1 year ago
A) Work out 5% of 240
Pani-rosa [81]

Answer:

12 sorry if its wrong

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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