Answer:
Step-by-step explanation:
The hyperbola has x-intercepts, so it has a horizontal transverse axis.
The standard form of the equation of a hyperbola with a horizontal transverse axis is 
The center is at (h,k).
The distance between the vertices is 2a.
The equations of the asymptotes are
1. Calculate h and k. The hyperbola is symmetric about the origin, so
h = 0 and k = 0
2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6
a = 6/2 = 3
3. For 'b': The equation for the asymptote with the positive slope is
Thus, asymptote has the slope of
4. The equation of the hyperbola is
The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.
Answer:
The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)
<u>Solution:</u>
Given, equation is 
We have to find the vertex of the given equation.
When we observe the equation, it is a parabolic equation,
We know that, general form of a parabolic equation is
Where, h and k are x, y co ordinates of the vertex of the parabola.
By comparing the above equation with general form of the parabola, we can conclude that,
a = -6, h = 1 and k = 9
Hence, the vertex of the parabola is (1, 9).
Answer:
B. 1/9
Step-by-step explanation:
The positive square root of "x^2 - 4x + 4" is "x - 2". That value is already given to you, 1/3. Just square 1/3 to get 1/9.
Answer:
The answer is D
Step-by-step explanation:
If you look very closely at the graphs you can see which one is the best answer
