First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
Answer:
I believe the answer is C. 0.75
Step-by-step explanation:
Answer:
B) All real values of 'x' where -2 < x< 4
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given function f(x) = (x +2 ) ( x-4)
(x+2)(x-4) =0
⇒ x +2 =0 and x-4=0
⇒ x =-2 and x=4
From graph
Given parabola lies between the x=-2 and x =4
∴ All real values of 'x' lies between x=-2 and x =4
All real values of 'x' lies -2 < x< 4
Answer:
None of them are correct i believe
Step-by-step explanation:
its sideways lol
Answer:I think it is C
Step-by-step explanation:I think it i C
