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WARRIOR [948]
3 years ago
12

Given square NOWR, what is the value of x and y?

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

x = 4, y = 9

Step-by-step explanation:

The angles in a square are right, that is 90°

The diagonals bisect the angles , then

6x + 21 = 45 ( subtract 21 from both sides )

6x = 24 ( divide both sides by 6 )

x = 4

------------------------------------------------

The sides of a square are congruent , then

10y - 29 = 5y + 16 ( subtract 5y from both sides )

5y - 29 = 16 ( add 29 to both sides )

5y = 45 ( divide both sides by 5 )

y = 9

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iris [78.8K]

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I only figured out two points which is (0,2) (1,3)

Step-by-step explanation:

8 0
2 years ago
4/5 as an equivalent fraction in 3 different forms.​
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Equivalent fraction of ⅘:

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3 years ago
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!
Inessa [10]

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Step-by-step explanation:

3 0
2 years ago
V= 512^2/3* 19683^1/3*256^1/4
irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4    = 6912

Step-by-step explanation:

V= (512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times  (256^{\frac{1}{4} } )\\

As

2^{9}  = 512\\2^{8} =  256\\19683^{\frac{1}{3} } = 27\\

putting values in equation

V= 2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\  let it be equation 1

As

2^9^{\frac{2}{3} }  = 2^6    according\,to\,exponential\,rule\\2^8^\frac{1}{4} =     2^2     according\,to\,exponential\,rule\\\\

putting values in equation 1

V= 2^6\times 27\times 2^2

According to exponential rule 2^6 \times 2^2 = 2^8

V=2^8 \times 27\\

V=256\times 27\\V=6912

So

V= 6912

Keywords: Algebra

Learn more about algebra at:

  • brainly.com/question/3739260
  • brainly.com/question/13168205
  • brainly.com/question/9607945

#learnwithBrainly

7 0
3 years ago
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