All categories

2 years ago

which of the following is the equation of a line in slope-intercept form for a line with slope = 1/2 and y intercept at (0,-4)?

Mathematics

1 answer:

oee [108]2 years ago

7 0

Answer:

y = $\frac{1}{2}$ x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{1}{2}$ and c = - 4 , then

y = $\frac{1}{2}$ x - 4 ← equation of line

You might be interested in

What is the exact value of the exponential equation, 4(10)5x=200 ?

Rasek [7]

Answer:

4(10)5x=200 = x=log50 / 5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

When asked to factor the trinomial x^2-16x+64, a student gives the answer (x – 8)(x + 8). Which of the following statements is t

Murrr4er [49]

Answer:

The answer is incorrect; the plus sign should be a minus sign (apex)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please assist me in my time of need.

vaieri [72.5K]

Answer:

I shall assist thee.

Step-by-step explanation:

Being me, I would say the answer is A. or B. But i'd prolly go with A tbh.

And oofers on me if this ain't what you need.

4 0

3 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

2 years ago

Helppppp............

Arlecino [84]

Answer:

V=lwh

4x6x3

v=72

3 0

2 years ago

Read 2 more answers