Question

-2n( m^2 - m -3 ) =

Answer 1

Answer:

$=-2nm^2+2nm+6n$

Step-by-step explanation:

$-2n\left(m^2-m-3\right)\\\mathrm{Distribute\:parentheses}\\=\left(-2n\right)m^2+\left(-2n\right)\left(-m\right)+\left(-2n\right)\left(-3\right)\\Apply\:minus-plus\:rules\\+\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab\\=-2nm^2+2nm+2\cdot \:3n\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6\\=-2nm^2+2nm+6n$

Answer 2

Answer: $-2nm^{2} +2nm+6n$

Step-by-step explanation:

Expand by distributing terms.

$-(2nm^{2} -2nm-6n)$

Remove parentheses.

$-2nm^{2} +2nm+6n$