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inna [77]
3 years ago
8

Guys pls help

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f   brainliest ?

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Plz help me i need it
Mila [183]

Answer:   4

<u>Step-by-step explanation:</u>

f(x) = 4x³ - x² + 1        g(x) = x - 1

                                 g(2) = (2) - 1

                                        = 1

f(1) = 4(1)³ - (1)² + 1

     =  4   -   1   + 1

<h2>      = 4</h2>

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