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adoni [48]
3 years ago
14

Five sixth-grade classes collected canned food for the local food bank. Each class collected a different number of cans. Use the

following clues to determine how many cans were collected in each class.
The five classes that collected cans include two classes with totals in the three hundreds, two classes with totals in the four hundreds, and one class with a total in the five hundreds.
The smallest total was 308 cans.
The range of the total cans collected was 262.
The median number of cans collected was 421.
The total of the two classes in the three hundreds was 706.
The total number of cans collected from all the classes was 2,130 cans.


List the classes from least to greatest.
Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

308, 398, 421, 433, 570

Step-by-step explanation:

To start we know the smallest is 308 cans, so that is the first class.

Next, it says the range is 262. The range is maximum minus the minimum. Since we know the minimum(308), that means 308 + 262 = 570 and 570 is the maximum or the class with most collected cans.

Then, it says the median or the middle number is 421, the middle number in a class is 3. So, the third class collected a total of 421 cans.

After that, it says the two classes in the three hundred, or the first and second class, has a total of 706 cans. So, if we do 706 - 308 we get the second class. Which collected 398 cans.

Finally, it says the total all the class collected is 2130. So, if we add all the values we have know and subtract it from the total of all the class we get the missing class or the fourth class. So, 308 + 398 + 421 + 570 = 1697, and 2130 -1697 = 433. Which the fourth class.

Least to greatest:

308

398

421

433

570

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A city in the Pacific Northwest recorded its highest temperature at 91 degrees F and its lowest temperature at 12 degrees F for
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Answer:

(A)12-19

Step-by-step explanation:

To construct a frequency distribution, we follow the steps below.

1. Find the largest and smallest values.

91 and 12 respectively

Compute the Range = Maximum - Minimum=91-12=79

2. Determine the number of classes desired.

In this case, we desire 10 classes

3. Next, we find the class width by dividing the range by the number of classes and rounding up.

79÷10 = 7.9

Rounded Up, Class Width=8

4. Pick a suitable starting point less than or equal to the minimum value.

Since our minimum value is 12, we pick a class starting with 12 and give a class width of 8.

Therefore the upper and lower limits of the first class is given as:

12-19.

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4 years ago
Really important!! Please help!!:
Drupady [299]

Answer:

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3 0
2 years ago
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A set of data with 1200 numbers is normally distributed with a mean of 27 and a standard deviation of 4. How many numbers in the
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Step-by-step explanation:

The mean is 27 and the standard deviation is 4.

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5 0
4 years ago
What is the value of x?
MariettaO [177]
It’s d hope this helps
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Start by combining like terms -2x + -3x = -5x. 7 + -9 = -2. You should get -5x - 9.
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