Answer:
n+(n+2)+20=4n
Step-by-step explanation:
Let the smaller integer be n,
the bigger odd integer will be n+2.
n+(n+2)+20=4n
2n+22=4n
2n=22
n=11



There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.
Along the boundary
, we have

which attains a maximum value of

Along
, we have

which attains a maximum of

Along
, we have

which attains a maximum of

So over the given region, the absolute maximum of
is 1578 at (2, 44).
I don’t not know what this I’m only in the 5th gradensns
The intercept is -25 because for a quadratic equation in the form

the c value or the number without a variable attached is the y intercept
Answer:
5.14 km
Step-by-step explanation:
A semicircle is 1/2 of a circle so the perimeter is just 1/2 of the circumference
C = 2 * pi r for a circle so for a semicircle
1/2* 2* pi *r
pi*r
3.14 * 1
3.14
If we want to include the piece that closes the semicircle, we need to add the diameter
d = 2r = 2(1) = 2
2+3.14 = 5.14