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2 years ago

I only need help with #15

Mathematics

2 answers:

svetlana [45]2 years ago

6 0

Answer:

hai

Step-by-step explanation:

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vlabodo [156]2 years ago

6 0

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You might be interested in

(10+-7 - -2) / (-2 - -1)

Scrat [10]

Nice use of brackets. We know exactly what you mean.

(10 - 7 + 2) / (-2 + 1) Notice that with an even number of - signs, you get a plus and with and odd number you get a minus.

(5) / (-1) = - 5 answer

Edit

Numerator

10 does not change.

+ - 7 Here a plus and a minus are put together. There is 1 minus sign which is an odd number of minus signs so the 7 is minus

- - 2 Here there are 2 minus signs. They become plus because 2 is even, and an even number of minuses become a plus so you have +2

10 - 7 + 2 = 5

Denominator

-2 does not change. It remains minus 2.

- - 1 There are 2 minus signs so this becomes plus 1.

- 2 + 1 = - 1

Numerator over denominator = 5/-1 = - 5. I'll probably run out of editing time. If you still don't understand, try and pinpoint the problem and we'll keep trying until you do see it. This question is worth it.

4 0

3 years ago

Read 2 more answers

find the vertex, the equation and axis of symmetry, and the y-intercept of the graph of y=-3x^2-13x+3

stepladder [879]

Answer:

Vertex: (13/6,-133/12)

Axis of symmetry: x=13/6

y-intercept: y=3

Step-by-step explanation:

6 0

2 years ago

PLEASE HELP.

krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) $DE=4\sqrt{10}\ cm$

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

$AE^{2}=AC^{2}+CE^{2}$

substitute the values and solve for CE

$14^{2}=6^{2}+CE^{2}$

$CE^{2}=14^{2}-6^{2}$

$CE^{2}=160$

$CE=\sqrt{160}\ cm$

$CE=4\sqrt{10}\ cm$

remember that

CE=DE

$DE=4\sqrt{10}\ cm$

7 0

3 years ago

PLEASE HELP! 10 POINTS!

Goshia [24]

A quotient means division, so you can get rid of the third and fourth choices. It says "opposite" so that means negative. The answer is the second choice: $\frac{(-x)^{2} }{3}$

7 0

3 years ago

A kite is a quadrilateral which has 2 sides next to each other that are congruent and where the other 2 sides are also congruent

MrRa [10]

Answer:

Step-by-step explanation:

Given: Kite WXYZ

Prove: That at least one of the diagonals of a kite decomposes the kite into 2 congruent triangles.

A diagonal is a straight line from one vertex to another of a given shape or figure.

Considering diagonal WY of the kite,

<WYZ ≅ <WYX (diagonal WY is the bisector of <Y)

<ZWY ≅ <XWY (diagonal YW is the bisector of <W)

WZ ≅ WX (congruent property)

YZ ≅ YX (congruent property)

Thus,

ΔWYZ ≅ ΔWYX (Angle-side-Angle congruent property)

Therefore, the given kite can be decompose into 2 congruent triangles (ΔWYZ and ΔWYX).

8 0

2 years ago