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algol13
2 years ago
12

A factory is to be built on a lot measuring 150 ft by 200 ft. A local building code specifies that a lawn of uniform width and e

qual in area to the factory must surround the factory. What must the width of this lawn be, and what are the dimensions of the factory?
width of lawn ft
factory dimensions ft (smaller length) by ft (larger length)
Mathematics
1 answer:
Lyrx [107]2 years ago
3 0

Answer:

30000

Step-by-step explanation:

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Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day
AfilCa [17]

Answer:

Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = 5\frac34 \ hrs.

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

5\frac34 \ hrs. can be Rewritten as \frac{23}{4}\ hrs

Number of hours rode on first day = \frac{23}{4}\ hrs

Also Given:

Number of hours rode on second day = 6\frac45 \ hrs

6\frac45 \ hrs can be Rewritten as \frac{34}{5}\ hrs.

Number of hours rode on second day = \frac{34}{5}\ hrs.

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = 20-\frac{23}{4}-\frac{34}{5}

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = \frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day =\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.

Hence Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

3 0
3 years ago
Jackson says has an odd number of model cars.he has 6 cars on one shel and 8 cars on another shelf.is jackson correct?explain
grigory [225]
No. It's rather simple, down to addition. Ask yourself, what does 6 + 8 equal? 6 + 8 = 14. Now is this an odd number? No, 14 is an even number.

I hope this helps! If not I'm sorry. 
4 0
3 years ago
Solve by substitution: <br> Y= 2x+5 <br> Y=2x+1
julia-pushkina [17]
Just put down no solution. It's unsolvable.
3 0
4 years ago
The circle graph shows a family budgets it’s annual income.if the total annual income is 140,000, what amount is budgeted for au
emmasim [6.3K]

Answer: The amount budgeted for Auto Expenses is $18,200

Step-by-step explanation:

13 Percent of $140,000 is $18,200

0.13 times 140,000 :-)

5 0
3 years ago
A sidewalk forms the diagonal of a square park. The sidewalk is 30 meters long. To the nearest tenth of a meter, how long are th
PtichkaEL [24]
<span> <span>We can use the Pythagorean Theorem (A² + B² = C²) to solve for the lengths of the sides. We know that the diagonal, C, is 30 meters long, so C² = 900 meters. We know that since the park is square, A² + B² = 2A² = 2B²

900 = 2A²

A^2 = 450

Taking the square root of 450, we find that the lengths of A and B are roughly 21.2 meters.</span> </span>
8 0
3 years ago
Read 2 more answers
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