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3 years ago

Write the coordinates of one point that lies in the second quadrant of the coordinate plane.

Mathematics

1 answer:

iren [92.7K]3 years ago

4 0

Answer:

Examples are: (-1,1), (-2,1), and (-3,1).

Step-by-step explanation:

The second quadrant on a coordinate plane is located in the top left.

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I need help with #10

borishaifa [10]

Answer:

Step-by-step explanation:

this seems to be the line of best fit as it is centered in the data.

hope this helps!!

4 0

3 years ago

Determine whether the three points are the vertices of a right triangle. (6, -6), (9, -6), (9, 1)

lisabon 2012 [21]

Answer:

The three given points are the vertices of a right triangle.

Step-by-step explanation:

To determine that the three points are the vertices of a right triangle let us find the distance between each two points

The formula of the distance is $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

∵ $x_{1}$ = 6 and $y_{1}$ = -6

∵ $x_{2}$ = 9 and $y_{2}$ = -6

∴ $d_{1}$ = $\sqrt{(9-6)^{2}+(-6--6)^{2}}=\sqrt{9+0}$

∴ $d_{1}$ = 3

∵ $x_{1}$ = 6 and $y_{1}$ = -6

∵ $x_{2}$ = 9 and $y_{2}$ = 1

∴ $d_{2}$ = $\sqrt{(9-6)^{2}+(1--6)^{2}}=\sqrt{9+49}$

∴ $d_{2}$ = $\sqrt{58}$

∵ $x_{1}$ = 9 and $y_{1}$ = 1

∵ $x_{2}$ = 9 and $y_{2}$ = -6

∴ $d_{3}$ = $\sqrt{(9-9)^{2}+(-6-1)^{2}}=\sqrt{0+49}$

∴ $d_{3}$ = 7

<em>Let us use the fact that if the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side</em>

∵ The longest side is $\sqrt{58}$

∵ The other two sides are 3 and 7

∵ ( $\sqrt{58}$ )² = 58

∵ (3)² + (7)² = 9 + 49 = 58

∴ ( $\sqrt{58}$ )² = (3)² + (7)²

- By using the fact above

∴ The triangle is a right triangle

The three given points are the vertices of a right triangle.

8 0

4 years ago

Who know the correct answer to this

miskamm [114]

y = -x + b

Plugging in the point

-13 = -7 + b

-6 = b

Answer: -6

8 0

3 years ago

Find the domain and range of the exponential function h(x)= -343^x

givi [52]

I will named this exponential function as y= - 343^x .
This function is symmetrical with function y = 343^x in relation to X axis.
In general their formula is y=a^x or in your case y= - a^x

First I'll describe y=a^x => this function has domein Dx=R ( Whole field of real number), range is in interval ( 0, +infinity), when x increases and y increases, when x decreases and y decreases. This function is always positive in whole domain and always is growing function. And X axis is its asymptote (y=0).

In your case function y= - 343^x has folowing features:
domein Dx=R
range is in interval (-infinity, 0)
when x increases => y decreases =>
example: y= -2^2=-4, y= -2^3=-8 etc....
when x decreases => y increases ->
example: y= -2^(-2)= - 1/(2^2)= - 1/4, y=-2^(-3)= - 1/(2^3)= - 1/8 etc....
this function is always negative
this function is always declining
x axis is its asymptote from the top ( y=0)

7 0

3 years ago

Pls help me I’m failing math

Natalka [10]

Answer:

C. Pages per hour.

Best of luck for the exam tho :)

SInce people are getting mad, I'm making this edit to say,

$\frac{pages}{hour}$ × the number of hours = pages, which is the answer.