All categories

2 years ago

The lines P an Q intersect at point O. What is the value of x?

Mathematics

1 answer:

Pani-rosa [81]2 years ago

5 0

Answer:

Step-by-step explanation:

you add the b and x coordinate divide it by 2 to get the value of p and q which you then divide by the value of ur mom to get x

You might be interested in

This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false

nlexa [21]

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

8 0

2 years ago

-4x+y=23 and 4x-9y=-15

astra-53 [7]

Answer: x= -6; y= -1

Step-by-step explanation:

-4x + y = 23

4x - 9y = - 15

-4x + y = 23

y = 23 + 4x [Add 4x to both side]

4x - 9(23 + 4x) = - 15

4x - 207 - 36x = - 15

-32x - 207 = -15

-32x = 192 [Add 207 to both side]

x = -6 [Divide -32 from both side]

-4x + y = 23

-4(-6) + y = 23 [Plug in -6 for x]

24 + y = 23 [Subtract 24 from both side]

y = -1

5 0

2 years ago

How many terms are in -7k+x2-3

liq [111]

Answer: 2 terms 1:k 2:x

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Is the sum of the

Olin [163]

Answer
Yes

Explanation
I just know

8 0

2 years ago

In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo

Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

$P(B) = 0.6$

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

$P(A/B) = x$

P(A) is the probability that the participant dies:

$P(A) = P_{1} + P_{2} + P_{3}$

$P_{1}$ is the probability that a heavy smoker is selected and that he dies. So:

$P_{1} = 0.15*5x = 0.75x$

$P_{2}$ is the probability that a light smoker is selected and that he dies. So:

$P_{2} = 0.25*3x = 0.75x$

$P_{3}$ is the probability that a non-smoker is selected and that he dies. So:

$P_{3} = 0.60*x = 0.60x$

The probability that a participant dies is:

$P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x$

The probability of the participant being a non-smoker, given that he died, is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857$

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0

3 years ago