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Roman55 [17]
3 years ago
10

Solve for g. –19g = –20g + 12 g =

Mathematics
2 answers:
VikaD [51]3 years ago
7 0

Answer:

g = 12

Step-by-step explanation:

<u>→The first step is to add 19g to both sides:</u>

-19g = -20g + 12

+19g   +19g

____________

0 = -g + 12

<u>→Subtract 12 from both sides:</u>

0 = -g + 12

-12       -12

_________

-12 = -g

<u>→Divide both sides by -1:</u>

12 = g

Vera_Pavlovna [14]3 years ago
4 0

Answer:

g = 12

Step-by-step explanation:

–19g = –20g + 12

Add 20 g to each side

–19g+20 g = –20g+ 20g + 12

g = 12

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Which is bigger, one fourth of 16 or one third of 24? Explain and show work please.
adoni [48]
1/4 x 16
= 16 ÷ 4
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= 8

8 is greater than 4, so one third of 24 is bigger than one fourth of 16
feel free to ask questions if you are still confused!


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The sumof a number and 48 is -18
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<u>⇒If the unknown x;</u>

48 + x = -18

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x = -18-48

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4 years ago
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What is 72/75 in simplest form
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3 years ago
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Point Q is on line segment PR. Given QR = 3x, PQ = x + 6, and
nadya68 [22]

Given:

Point Q is on line segment PR.

QR = 3x, PQ = x + 6, and  PR = 5x – 4.

To find:

The numerical length of PQ.

Solution:

Since, point Q is on line segment PR, so by segment addition property, we get

PR=PQ+QR

5x-4=(x+6)+3x

5x-4=4x+6

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The value of x is 10.

Now,

PQ=x+6

Putting x=10, we get

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3 years ago
Sketch the sinusoidal function that passes through (0,-6) , has a period of 12 and an amplitude of 3
riadik2000 [5.3K]

The sinusoidal function that passes through (0,-6), has a period of 12 and an amplitude of 3 will be y = 3 sin 12x - 6.

What is a sinusoidal Function?

It is a function that repeats itself in a particular time interval.

The equation is given as

y = Asin (ωx + Ф) + k

We have

Amplitude (A) = 3

Period (ω) = 12

Phase difference (Ф) = 0

Then the equation will be

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The function is passing through (0, -6). Then we have

-6 = 3sin (12 × 0) + k

-6 = k

Then the equation will be

y = 3 sin 12x - 6

More about the sine function link is given below.

brainly.com/question/3876065

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4 0
2 years ago
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