All categories

3 years ago

Help me pls guys! im being timed and need some help!

Mathematics

2 answers:

Agata [3.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

she only has $60 to spend therefore, she has the option of spending all of it, or less. However she cannot spend money she doesn't have.

Alborosie3 years ago

3 0

Answer:

I think it's B

Step-by-step explanation:

(So far she has spent $45.95, plus the extra gift, and that has to equal less than or equal to $60) =

45.95 + extra gift (x) ≤ 60

You might be interested in

Write a system of equations in x and y describing the situation. Do not solve the system. Keiko has a total of $ 5600 comma$5600

IgorLugansk [536]

Answer:

The correct answers are x + y = 5600 and x - y = 700.

Step-by-step explanation:

Write a system of equations in x and y describing the situation. Do not solve the system.

Keiko has a total of $ 5600, which she has invested in two accounts.

Let x be the amount of money in the larger account and y be the amount of money in the smaller account.

So, Keiko has invested her $5600 in two accounts x and y.

Thus x + y = 5600.

Also, given by the problem, the larger account (x) is $ 700 greater than the smaller account (y).

Thus x - y = 700.

Thus the two system of equation in x and y describing the given situation are

x + y = 5600 and x - y = 700

8 0

3 years ago

Find the slope of the line that passes through the pairs of points ( 7, 4), (-4,5)

lilavasa [31]

Answer:

The slope is 1/-11.

Step-by-step explanation:

Slope (m) =

ΔY /ΔX =

1 /-11 = -0.090909090909091

7 0

3 years ago

Use the midpoint formula to estimate the sales of Cars, Inc. in 2009, given the sales in 2008 and 2010. Assume that the sales of

lana [24]

Answer:

<em>The estimated sales were $260 million</em>

Step-by-step explanation:

Assume the endpoints of a segment are (x1,y1) and (x2,y2).

The midpoint (xm,ym) is calculated as follows:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The sales ov Cars, Inc. were (2008,240 million) and (2010,280 million). We need to use the midpoint to estimate the sales in 2009:

$\displaystyle x_m=\frac{2008+2010}{2}=2009$

$\displaystyle y_m=\frac{240+280}{2}=260$

The estimated sales were $260 million

5 0

3 years ago

DIscrete Math

Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

$f : X \rightarrow Y$ is surjective implies there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ .
If there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ , then $f : X \rightarrow Y$ is surjective

Let us start by the first implication.

Our hypothesis is that the function $f : X \rightarrow Y$ is surjective. From this we know that for every $y\in Y$ there exist, at least, one $x\in X$ such that $y=f(x)$ .

Now, define the sets $X_y = \{x\in X: y=f(x)\}$ . Notice that the set $X_y$ is the pre-image of the element $y$ . Also, from the fact that $f$ is a function we deduce that $X_{y_1}\cap X_{y_2}=\emptyset$ , and because $f$ the sets $X_y$ are no empty.

From each set $X_y$ choose only one element $x_y$ , and notice that $f(x_y)=y$ .

So, we can define the function $h:Y\rightarrow X$ as $h(y)=x_y$ . It is no difficult to conclude that $f\circ h(y) = f(x_y)=y$ . With this we have that $f\circ h=1_Y$ , and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function $h:Y\rightarrow X$ such that $f\circ h=1_Y$ .

Take an element $y\in Y$ , then $f\circ h(y)=y$ . Now, write $x=h(y)$ and notice that $x\in X$ . Also, with this we have that $f(x)=y$ .

So, for every element $y\in Y$ we have found that an element $x\in X$ (recall that $x=h(y)$ ) such that $y=f(x)$ , which is equivalent to the fact that $f$ is surjective. Therefore, the prove is complete.

3 0

3 years ago

I NEED HELPPP<br><br> Whats the length of LN?

andre [41]

Answer:

LN = 66 cm

Step-by-step explanation:

The 3 parallel lines divide the 2 sides they intersect in proportion, that is

$\frac{DE}{EF}$ = $\frac{LM}{MN}$ , substitute values