All categories

3 years ago

G(x) = x2 − 4, find g(5).

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

g(x) = x2 - 4

g(5)= 5(2) - 4

g(5)= 10 - 4

g(5)= 6

Have a great day

You might be interested in

What is 23.70 divided by 8.1 laid out

tester [92]

Answer:

2.925925926 or 2.9

Step-by-step explanation:

23.7/8.1

= 2.925925926 or approximately 2.9

3 0

3 years ago

Jane has 6 more than twice the number of pairs of shoes that Mary has.

goldfiish [28.3K]

Answer:

im not sure

Step-by-step explanation:

6 0

2 years ago

Find the domain and range of f(x) = 2 square root of x-2

Neporo4naja [7]

$f(x)=2\sqrt{x-2}\\\\The\ domain:\\x-2\geq0\to x\geq2\\\boxed{x\in[2;\ \infty)}\\\\The\ range:\\\boxed{y\in[0;\ \infty)}$

$If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}$

5 0

3 years ago

Please please help me please help please please help me please help please

AVprozaik [17]

Answer:

Perimeter is 17.07

Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

We need to use the Pythagorean theorem to get the length of DE.

$DE = \sqrt{5^{2} +5^{2}}=\sqrt{50} = 7.07\\$

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07

5 0

3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago