consider the numbers are x,2x,3x,4x,5x
Given;
(x+2x+3x+4x+5x)/5 = 11
15x = 55
x= 55/15 = 11/3
The numbers are
11/3, 22/3, 11, 44/3, 55/3
Lol I don’t understand that language
Answer:
2
Step-by-step explanation:
loge(x) is ln(x)
f(x) × ln(x)
Differentiate using product law
[ln(x) × f'(x)] + [(1/x) × f(x)]
x = 1
[ln(1) × f'(1)] + [(1/1) × f(1)]
(0 × 4) + (1 × 2)
0 + 2
2
Answer: 22/20 in simplest form would be 11/10.
Step-by-step explanation:
To find simplest form, you need to reduce the fraction down by a common factor, for instance 2. 22/2 is 11 (which is your numerator) and 20/2 is 10 (which is your denominator).