3 years ago

If ABCD were reflected across the x-axis, A' would be located at (1,4). True False

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

False. It would be (-1,-4)

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Pls help me I am confused

Maslowich

Answer:

$\huge\boxed{A.\ \dfrac{565}{182}}$

Step-by-step explanation:

$\dfrac{8}{7}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{8}{7}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by 35}\\\\35\cdot\dfrac{8}{7}-35\cdot5x+35\cdot3=35\cdot\dfrac{1}{5}x-35\cdot12\qquad|\text{simplify}\\\\5\cdot8-175x+105=7\cdot x-420\\\\40-175x+105=7x-420\\\\-175x+(40+105)=7x-420\\\\-175x+145=7x-420\qquad|\text{subtract 145 from both sides}\\\\-175x=7x-565\qquad|\text{subtract }7x\ \text{from both sides}\\\\-182x=-565\qquad|\text{divide both sides by (-182)}\\\\x=\dfrac{565}{182}$