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djverab [1.8K]
3 years ago
8

Geometry 12 16 2020​

Mathematics
1 answer:
Phantasy [73]3 years ago
7 0
Answer: A) 2/3

Method: Here’s an easy method for questions like these, when you are looking at a triangle, look at the angle that’s away from the biggest line (if it’s a right triangle choose any angle), for this case angle W. Now count how many lines it takes to get to the big line, for the original triangle it’s 6 and for the new triangle it’s 4. Now since you have your numbers turn it into a fraction (new on top original on bottom), 4/6. Finally see what the answer is, for this case 4/6 is equal to 2/3, so there’s your answer.
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Find value of variable
Nezavi [6.7K]
<span>Step 1: Identify the variables.
Step 2: Add/Subtract whole numbers so they're all on one side.
Step 3: Add/Subtract Variables so they're all on one side.
Step 4: Multiply /Divide to get the variable by itself.
<span>Step 5: Check your work.</span></span>
4 0
4 years ago
10x-2y=18 8x=y solve by substitution
lana [24]

Answer:

x = -1 and y = 18

Step-by-step explanation:

Given the system of equations

y + 8x = 10... 1

2y - 4x = 40 ... 2

From 1; y = 10-8x

Substitute into 2;

2(10-8x) - 4x = 40

20 - 16x - 4x = 40

20 - 20x = 40

-20x = 40 - 20

-20x = 20

x = -1

Recall that y = 10-8x

y = 10 - 8(-1)

y = 10 + 8

y = 18

therefore your answer is  x = -1 and y = 18

4 0
3 years ago
Read 2 more answers
F(x) = -x + 5, what is the value of f(-4)?<br> I
liberstina [14]

Answer:

Step-by-step explanation:

F(x)=-x+5

So

f(-4)= -(-4)+5

f(-4)= 4+5

f(-4)= 8

Only we have to substitute value of x then after simplification we will get answer..Hope this will help

7 0
3 years ago
Read 2 more answers
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
Which data set was used to create this graph?
Vika [28.1K]
Where is the graph?.........
7 0
3 years ago
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