The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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Answer:
I win 10% = 217.8
I lost 10% = 178.2
217.8 + 178.2 = 396
198 + 198 = 396
396 = 396
I neither gain nor lose anything: V
Step-by-step explanation:
Answer:
MK
Step-by-step explanation:
ML is the short side of right triangle MLK. MJ is the hypotenuse of right triangle MKJ. This gives you a clue that the ratios of interest are the short side to the hypotenuse. All these right triangles are similar, so ...
ML/MK = MK/MJ . . . . . ratio of short side to hypotenuse is the same
ML·MJ = MK² . . . . . . . cross multiply
MK = √(ML·MJ) . . . . . the geometric mean of ML and MJ is MK
Answer:
20,000 divided by 4,250
Step-by-step explanation:
