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nikdorinn [45]
3 years ago
15

Will mark bianleast

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
Left 7 units and up 3 units
Ivanshal [37]3 years ago
6 0

Answer

7 Units left and 3 units up

Step-by-step explanation:

Rise over Run

Up 3 and to the left 7

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Factor the Following:<br><br>1.) 8<br>2.) -12<br>3.) -3y²<br>4.) 6x²+36x<br>5.) 7x -14x²​
Alex787 [66]

Answer:

1.) 8 = 8

2.) -12 = -12

3.) -3y² = -3y²

4.) 6x² + 36x = 6x(x + 6)

5.) 7x - 14x² = 7x(1 - 2x)

~

3 0
3 years ago
Why are 7 and 2 like terms? help please!!
bazaltina [42]

Like terms are terms whose variables are the same. In this case, 7 and 2 have no coefficients therefore are like terms. For example, 7x and 2x would both be like terms because they have the same coefficient which is x.

7 0
3 years ago
Which rate describes a unit price?
jarptica [38.1K]
<h2>Answer: <u><em>$5.00 for 1 day</em></u></h2>

Step-by-step explanation:

Unit price refers to the price of an item in one unit (one), 1 in quantity in particular. $5.00 goes in daily pricing - 1 day. While the others are pricing in multiple units.

3 0
2 years ago
Read 2 more answers
Need help don’t understand
seraphim [82]
1. 2x and 6y Because
y = 2x + 6
4 0
3 years ago
Given that log3(z - 1) - logz z = 1+ 3 log3 y, express z in terms of y.
fgiga [73]

Answer:

  z = 1 + 9y³

Step-by-step explanation:

It looks like you have ...

  \log_3{(z-1)}-\log_z{(z)}=1+3\log_3{(y)}\\\\\log_3{(z-1)}-1=1+\log_3{(y^3)}\\\\\log_3{(z-1)}=2+\log_3{(y^3)}\qquad\text{add 1}\\\\z-1=(3^2)(y^3)\qquad\text{take antilog}\\\\\boxed{z=1+9y^3}\qquad\text{add 1}

6 0
3 years ago
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