Answer:
2300
Step-by-step explanation:
Put 8 into fraction form: 8/1
Put 1 2/5 into a mixed number: 1*5+2 as numerator and 5 as denominator (7/5)
Now multiply 8/1 by the reciprocal of 7/5, which is basically just the numerator and denominator flipped, so 5/7. This is like dividing.
8/1*5/7= 40/7
40/7= about 5.7.
So, your answer would be 5.7 batches, or 5 complete batches would be a better answer.
Answer: The constant of proportionality is 3.5, so your answer would be B.
Considering the conversion from exponent to radical, the equation that justifies why the expression
is correct is.

<h3>How is the conversion from exponent to radical realized?</h3>
The conversion of rational exponents to radical notation is modeled by:
![a^{\frac{n}{m}} = \sqrt[m]{a^n}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D%20%3D%20%5Csqrt%5Bm%5D%7Ba%5En%7D)
In this problem, the expression is:
![9^{\frac{1}{3}} = \sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B9%7D)
And the equation that shows that this is correct is:

More can be learned about the conversion from exponent to radical at brainly.com/question/19627260
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ANSWER
The solution is where the two graphs intersect, which is

EXPLANATION
The given system of equations are

and

We need to graph the two equations.
Let us graph

first.
We need at least two points.
You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.
When




So this gives us the ordered pair,

When

we get,




This also gives the ordered pair

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.
For the second line

We again find the intercepts and plot them.
When



This gives the ordered pair

Also, when

then we have,



Then we again have the ordered pair,

We plot these two points on the same graph sheet to obtain the red graph above.
The intersection of the two lines is

You will get good grades so don't worry much.