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Marysya12 [62]
4 years ago
7

Please help: Find the volume of the solid. Use 3.14 for π.

Mathematics
1 answer:
Kazeer [188]4 years ago
6 0

Answer:

The volume of the solid is 420m³

Step-by-step explanation:

The area of any pyramid is "1/3 · B · h", where B is the area of the base, and h is the height.

Knowing this we just need to solve for a couple of things.

First, and the easiest is the height of the triangle which (thankfully) is given to us. The height is 15m, which plus one number into our equation.

1/3 · B · 15

Second, we need to find the area of the base of the pyramid. That's done easily by finding the area of a triangle ( \frac{base * height}{2} → \frac{24*7}{2} → \frac{168}{2} → 84) giving us 84 units. This puts another number into our equation.

1/3 · 84 · 15

Now that we have all of the parts to our equation, we can solve it.

1/3 · 84 · 15

1/3 · 1260

420

The volume of the solid is 420m³

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Answer:

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As both sin\,\theta,

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\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

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