Options
A. Caroline rents exactly 7 games each month.
B. Caroline rents exactly 6 games each month.
C. Caroline rents 6 or more games each month.
D. Caroline rents from 1 to 5 games each month.
Answer:
D. Caroline rents from 1 to 5 games each month.
Step-by-step explanation:
Given
Plan A:
![C = 2n](https://tex.z-dn.net/?f=C%20%3D%202n)
Plan B:
![C = n + 6](https://tex.z-dn.net/?f=C%20%3D%20n%20%2B%206)
Required
Which options justifies A over B
The solution to this question is option (d).
In option d, n = 1,2,3,4,5
When any of the values of n is substituted in plan A and B, respectively; the cost of plan A is cheaper than plan B.
This is not so, for other options (A - C)
To show:
Substitute 1 for n in A and B
Plan A:
![= 2 * 1 = 2](https://tex.z-dn.net/?f=%3D%202%20%2A%201%20%3D%202)
Plan B:
![= 1 + 6 = 7](https://tex.z-dn.net/?f=%3D%201%20%2B%206%20%3D%207)
Substitute 5 for n in A and B
Plan A:
![= 2 * 5 = 10](https://tex.z-dn.net/?f=%3D%202%20%2A%205%20%3D%2010)
Plan B:
![= 5 + 6 = 11](https://tex.z-dn.net/?f=%3D%205%20%2B%206%20%3D%2011)
<em>See that A < B</em>