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2 years ago

Complete each trinomial such that it can be rewritten in the form a(x+b)^2 or a(x-b)^2

Mathematics

1 answer:

scoundrel [369]2 years ago

6 0

The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

<h3>Vertex Form of a quadratic expression</h3>

Given the quadratic expressions

1.5x^2+6x+......

1.5(x^2 + 4x)

Using the completing the square method

The coefficient of x = 4

Half of the coefficient = 4/2 = 2

The square of the result = 2^2 = 4

The equation is expressed as:

f(x) = 1.5(x^2+4x+ 4) - 4

f(x) = 1.5(x+2)^2 - 4

Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

Learn more on completing the square method here: brainly.com/question/1596209

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Which expression is equivalent to 6 x + 8?

miss Akunina [59]

Answer:

the 2nd one

Step-by-step explanation:

2*3x is 6x

2*4 is 8

equation is 6x+8

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3 years ago

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Answer of a ²-10a+16-6b-b^2

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$\quad a^2-10a+16-6b-b^2$

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

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3 years ago

6=1-2n+5 how do I solve this?

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$6=1-2n+5\\ \\2n=1+5-6\\ \\ 2n=0\ \ /:2\\ \\ n=0$

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2 years ago

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Last month a Carpenter made five tables this month he made 80% more than that how many tables do the carpenter make this month

Nataliya [291]

Answer:

9 tables

Step-by-step explanation:

5 × 1.8 = 9

to find how many tables he made you have to multiply the number he made by 1, then .(whatever the percent is)

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2 years ago

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Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

2 years ago