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matrenka [14]
2 years ago
14

What is 43.6925 rounded to the nearest thousands place

Mathematics
1 answer:
k0ka [10]2 years ago
8 0

Answer:

43.693

Step-by-step explanation:

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What is the theoretical probability of rolling a 3?
aleksandrvk [35]

Answer:

1/6

Step-by-step explanation:

the number on the bottom of the fraction (denominator) is equal to the total number of possibilities (in this case there are 6 possibilities). for the number on top (the numerator) we are trying to work out the probability of rolling a 3. a 3 is only 1 of the 6 options (1, 2, <u>3</u>, 4, 5, 6) so the number on top is 1.

I hope this was helpful :-)

7 0
3 years ago
Be a detective and solve this case: There are 53 bicycles in a room, and a man is dead on the floor next to them. Why was the ma
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<span>The 53 bicycles are the bicycle brand of playing cards. Since we all know that a deck contains 52 cards, he must have been cheating and he put another card in the deck. His buddy caught him and killed him</span>
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3 years ago
What if the following choices will simplify 7-5(3)^2
rewona [7]

Answer:

-38

Step-by-step explanation:

7-5(3)^2

PEMDAS

Since there are no parentheses to execute

Exponents next

7-5(3)^2

7-5*9

Multiply and divide next

7 - 45

-38

3 0
3 years ago
The following list gives the number of public libraries in each of 11 cities. 7, 11, 8, 7, 8, 7, 8, 11, 8, 10, 7 Find the modes
AlladinOne [14]

Answer:

The mode are: 7, 8

Step-by-step explanation:

Given

7, 11, 8, 7, 8, 7, 8, 11, 8, 10, 7

Required

Determine the mode

We start by arranging the given data in ascending order

The ordered data are:

7,7,7,7, 8,8,8,8, 10, 11, 11

From the above data.

7 has a frequency of 4

8 has a frequency of 4

10 has a frequency of 1

11 has a frequency of 2

The data with the highest frequency is the mode.

We can see that 7 and 8 both have frequencies of 4

<em>Hence, the mode are: 7, 8</em>

8 0
3 years ago
Read 2 more answers
How to find and discover what is m∠A?
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Answer: 113, 57, and 66

Step-by-step explanation:

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6 0
3 years ago
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