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steposvetlana [31]
3 years ago
6

what are two methods you can use to find the area of a square. I WILL GIVE BRAINLIEST I NEED HELP QUICKKKKK

Mathematics
2 answers:
Doss [256]3 years ago
4 0

Answer:

To find the area of a rectangle multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area. This is the same as saying length2 or length squared.

Step-by-step explanation:

KIM [24]3 years ago
3 0

Answer:

For a rectangle, you get the length and width and multiply them

For a Square, you have to find one side length and mulitply it by itself

or you can split the square with a diagonal into 2 triangles, get the area of each and add them up

or split the square in half and find the area of both rectangles and then add them together

Step-by-step explanation:

For example, if the measure of one side of a square is 5, because all the other lengths are the same, you do 5 times 5 which equals 25 or 5^2 which is 25

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Landon scored an 85% on his test. If he got 34 problems correct, how many were on the test?
Sergeu [11.5K]

Answer:

There are 40 problems on the test

Step-by-step explanation:

Let p = the number of problems on the test

The number of problems on the test times the percent correct is the number correct

p * 85% = 34

p * .85 = 34

Divide each side by .85

p * .85/.85 = 34/.85

p = 40

There are 40 problems on the test

6 0
2 years ago
A circle with radius of 2cm sits inside a 7cm×11cm rectangle. What is the area of the shaded region? Round your final answer to
olga2289 [7]

Answer:

64.43 cm2   :)

Step-by-step explanation:

look and download the file i gave to u

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7 0
3 years ago
What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)
xxMikexx [17]
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

3 0
3 years ago
Read 2 more answers
What numbers are divisible by 810
Andrews [41]
If only + numbers are acceptable, then the numbers divisible by 810 are represented by {810n}, where n = {0, 1, 2, 3, ... }
8 0
3 years ago
Solve each equation .just write the number answer <br><br><br> 12.-b= 12.5<br><br> -0.1 = 10c
melamori03 [73]
The first one is b=-0.5
6 0
3 years ago
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